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17. Confinement of positive ions and electrons with a static electric and magnetic field
Try to do a small experiment
First I will calculate what magnet is possible to build my self, or to buy.
Let´s assume we have a dc power supply of 100 W.
Electrical cable in Bricodepot.es: 2,5 mm2 -> 0,22 € / m (maximum current about 20 A, acc. internet search ------------------------------------------------------- Diameter electromagnet (solenoid) = 60 cm
N = 500 turns, 1 turn = 2 π r = 1,885 m, 500 turn = 942 m (207 €)
For copper the resistivity ρ = R . A/l = 1,7 . 10-8 ohm meter (R = electrical resistance, l = length, A = cross-sectional area)
R = 1,7 . 10-8 . 942 /( 2,5. 10-6 ) = 6.41 ohm
100 W -> P = I2 . R -> I =√( P /R) = √ (100 / 6,41) = 3,95 A
B = μ0 . N/l . I (see hyperphysics)
μ0 = 4.π.10-7 N·A−2 N = amount of windings l = length solenoid, let´s take 1 m I = current in A B= 4.π.10-7 . 500 . 3,95 / 1 = 2,48 . 10-3 T
rounded- > B = 25 gauss = 25 . 10-4 tesla --------------------------------------------------------
Diameter solenoid = 30 cm (with same lenght of cable)
N = 942 / ( 2 . π . 0,15) = 999
-> B = 50 gauss -------------------------------------------------------
Diameter solenoid = 15 cm (with same lenght of cable)
N = 942 / ( 2 . π . 0,075) = 2000
-> B = 4.π..10-7 . 2000 . 3,95/ 1 = 99 gauss
-------------------------------------------------------
Fig.1. The magnetic field of an electromagnet with an iron core r1 = ½.d1 Volume of the iron core = π (r1)2 . (m1 + m2 + m1 + m2 + g + π . (r2+.r1 ) . 2 ) Volume of curved part of iron core ≈ 2 . π (r1)2 . π . (r2+.r1 ) d1 = 15 cm (r1 = 0,075 m Volume = π (0,075)2 . (1 + 0,30 + 1 + 0,30 + 0,60 + π . (0,20 +0,075 ) . 2 ) = π (0,075)2 . (3,2 + π . 0,55 ) = 0,087 m3 = 87 . 10-3 m3
--------------------------------------- Only an iron core inside the solonoide: Volume = π (r1)2 . m1 = π (0,075)2 . 1 = 17,7 . 10-3 m3 -> mass = 139 kg We could divide it in 14 discs of 10 kg ------------------------------------------- Relative permeabiltiy μ/μ0 iron (99,8 % pure) = 5000 (Wikipedia) Bwith iron core = k B without core , k = μ/μ0 = 5000 ( http://hyperphysics.phy-astr.gsu.edu/hbase/magnetic/elemag.html#c4 ) B without core = 50 gauss -> x 5000 => Bwith iron core = 250000 gauss = 25 T (inside the core)
The
relative permeability of mumetal is 20000 , but mumetal saturates at
about 8000 gauss. The relative permeability of soft iron with 99.95 percent purity is a massive 200,000. ----------------------------------------------- Suppose we can create a magnetic field of 1000 gauss
Two negatively charged rings at -80kV. Fig. 2.
The electrons are injectet upwards vertically, just above the under ring. During the short simulation time the electrons stay confined. If the vacuum chamber would be filled with D2 gas, would this gas be ionized and would the electron cloud attract the D+ ions, more or less towards the centre?
Fig. 3.
The D+ are generated randomly all over the "vacuum chamber". No magnetic field, and a negative charge in the middle (small ring).
In the following link an electron gun is sold with an energy range: 1 eV to 100 keV and a beam current range: 1 nA to 20 mA kimballphysics.com/electron-gun-systems 1.10-9 A = 1.10-9 C/s ~ 1.10-9 C/s / (1,6.10-19 C) = 6,3. 109 electrons/s
According the simulation program the charge of the blue ring at - 200 kV is - 2,38E-6 C. See also: Calculations on the charged rings etc.
- 2,38E-6 C / (1.10-9 C) = 2380 s = 40 min
So if you use an electron gun with a current of 1 nA, and the electrons stay in the centre, after 40 minutes we would have a charge equivalent with a charged ring at -200 V With a electron gun of 20 mA, 20.106 times faster, in 0,12 ms.
Fig. 4.
In the centre there is a negative electrical
charge of -2,38E-6 C.
Could we generate a electron cloud with, more or
less, this charge?
If ionized, how many D+ iones will colide with
the wall of the vacuum chamber?
The charged rings can be outside the vacuum
chamber, in the air? It seems to be possible, see below.
Perhaps a kind of van der Graaf Generator can be used to charge the rings?
When operated, the dome of the Van de Graaff generator and anything in contact with it takes on a charge. This charge can be positive or negative depending on how the Van de Graaff generator is designed. Since like charges repel, this can have some entertaining consequences in electrostatics demonstrations.
Pasco.com/ Here a Van de Graaf Generator is sold which can generate a voltage of about 400 kV (not stated if positive or negative).
Equipment:
Tesla meter till 2,4 T, 269 €
Amazon cable unipolar 100 m , 50 € , 1000 m -> 500 €
Leroymerlin cable unipolar 2,5 mm2 100 m, 33 €, 1000 m -> 330 € www.superimanes.com/hilo-de-cobre/esmaltado/hilo-cobre-020-mm-10-kg-esmaltado
https://cerlasa.com/ Carpenteria metálico taller Cuerte de Huerva (for a steel tube 1 mtr x 15 cm diameter)
Neutron detector 1295 $
Vacuum-projects.net Vacuum chamber 1 mtr x 40 cm diameter 9000 € in stainless steel 304.
www.elementosmagneticos.com/ Fabricante de el electroimanes , electromagnets, Navarra/Spain
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20 February
2014 ..
by
Rinze
Joustra www.valgetal.com